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Why is |a bi| equal to the square root of a^2 b^2? If x = Cos A iSin A and y = Cos B iSin B, show that [(x y)(xy- 1)]/[(x-y)(xy 1)] = (Sin A Sin B)/(Sin A - Sin B)
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Why is |a bi| equal to the square root of a^2 b^2? Stuff about me, stuff about Nio (the IC me) and hey, just general stuff. :D

Im in ur profile lurking at teh bottom
-PIE-.
The answer is..
Nio <3 Enoh
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