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 Posted: Tue Feb 24, 2009 5:33 am
The notes state the formula is:
ax^2 + bx + c = 0
Roots: x = (-b + [Square Root of: b^2 - 4ac]) Divided by 2a
And the question I have is:
px^2 - 6x + p = 0 has equal roots
(a) Form a Quadratic Equation
(in terms of x)
(b) Decide whether b^2 - 4ac is equal, more than or less than 0.
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Posted: Sat Mar 07, 2009 1:44 pm
Look at the given formula. When will it return one result? When the +- part (the square root) is 0. (Actually this is the answer to task (b). Because the square root will be 0 when the expression under it is 0.)
So what you do is form an equation 6^2-4p*p=0 and solve p from it. Insert the solutions in the given equation. I'd solve both of them for x to make sure I got it right.
Ask to expand the explanation if anything was unclear.
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