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 Posted: Tue Apr 24, 2007 2:45 pm
My little sister has this assignement, and It's so hard! I have tried to my best exstent to help her, and even solve it for myself, but I just don't get it! Help anyone?
Jillianne has 38 bean-baggie animals, consisting of cats, dogs, bunnies, and bears. Use these clues to find out how many of each.
She has twice as many cats as dogs
She has 3 times as many cats as bunnies
She has 4 times as many bears as bunnies
So help us out?
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Posted: Tue Apr 24, 2007 5:09 pm
Here we go, when I tell you how to do it, you're going to go "oh..." c=catd=dogr=bunniesu=bears We have several equations already u=4r
c=3r
c=2d
3r=2d --> (3/2)r=d
38=c+d+r+u Ready... sub them in 38=3r+(2/3)r+r+4r
38=(8+3/2)r
76=19r
r=4 Sub some more u=4(4)
c=3(4)
3(4)=2d
38=3(4)+(3(4))/2+4+4(4)
38=12+6+4+16
38=38
c=12
d=6
r=4
u=16
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Posted: Thu Apr 26, 2007 2:42 pm
Oohhh!
You were right. Total Ohh-ation.
Thanks again!
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Posted: Thu Apr 26, 2007 3:59 pm
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Posted: Sat May 19, 2007 3:10 pm
Personally, though, I can't believe they exspect a 4th grader to manage that! Mabey a 8th grader, such as myself, but not a 10 year-old!
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Posted: Mon May 21, 2007 5:29 pm
Bubb1e1and Personally, though, I can't believe they exspect a 4th grader to manage that! Mabey a 8th grader, such as myself, but not a 10 year-old! I'm already through about half of differential equations, and i already finished calculus, so my approach to the problem might be different than the average fourth grader.
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Posted: Tue May 22, 2007 10:59 pm
Wow, our maths class was just taught about simultaneous equations this year. But then my class isn't particularly bright (we're not streamed anymore crying ), an they might have just wanted a fourth grader to use the guess and check method.
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